Plz help with these two questions xc fast

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Oct 15th, 2015

Thank you for the opportunity to help you with your question!

Question 8

Distance =vt+(at^2/2) where v = initial velocity, t=time and a= accelation

v=0, t=4.9 and a= 5.47

Therefore, distance =0+(5.47*4.9^2)/2 = 65.667


Question 9

The athlete swims  50 m to one end of the pool and 50 m back hence travels a distance of 100 m. However his/her displacement, which is the net distance traveled is zero(0) meters since the athlete gets back to his/her origin which is a zero displacement.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 15th, 2015

Thank you!!

Oct 15th, 2015

You're welcome. You can request on me for other questions in future.

Oct 15th, 2015

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