Need help with probability and statistic

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Geologist has identified potential independent drilling sights,and have estimated that each has a probability of 60%yielding a profitable oil well.The company wants to identify exactly 4 profitable wells

a)What is the expected number of wells that must be started to identify exactly 4profitable wells

b)If drilling is started on 10sights,what is the probability that fewer than 4profitable wells will be identified

c)What is the probability that the first 4 wells started will identify4 profitable well

Oct 15th, 2015

Thank you for the opportunity to help you with your question!

a)100* 4/60 = 6.667 wells = 7 wells

b)60/100 *4/10 = 0.24

c) 60% +60%+60%+60% = 240% = 240/100= 2.4

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 15th, 2015

correction part c

it is (and) so, we multiply

 60/100 *60/100*60/100*60/100= 0.1296

Oct 15th, 2015

I will aprpreciate your 5-STAR rating. Thanks in advance.

Oct 15th, 2015

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Oct 15th, 2015
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Oct 15th, 2015
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