Find a polynomial f(x) of degree 3 with real coefficients and the following zeros.
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If 2+i is a zero then 2-i should also be a zero of that polynomial.
hence,the zeros are -4, 2+i, 2-i
the polynomial is (x+4)(x-2-i)(x-2+i) =0
(x+4)(x^2-4x+5) = 0
x^3-4x^2+5x+4x^2-16x+20 = 0
x^3 - 11x + 20 =0
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