For the polynomial below, 3 is a zero.
f(x) = x^3 - x^2 - 12x -18
Express f(x) as a product of linear factors
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(x^3 - x^2 - 12x -18)/(x-3)=(x^2+2x-6)(x-3)-36
3 isn't a zero
maybe you write equation incorrectly?
I copied down the wrong equation! Im sorry! The correct equation is:
h(x)= 3x^3 - 13x^2 + 8x +12
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