For the polynomial below, 3 is a zero.

f(x) = x^3 - x^2 - 12x -18

Express f(x) as a product of linear factors

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(x^3 - x^2 - 12x -18)/(x-3)=(x^2+2x-6)(x-3)-36

3 isn't a zero

maybe you write equation incorrectly?

I copied down the wrong equation! Im sorry! The correct equation is:

h(x)= 3x^3 - 13x^2 + 8x +12

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