For the polynomial below, 3 is a zero.

f(x) = x^3 - x^2 - 12x -18

Express f(x) as a product of linear factors

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please check if

f(x) is correct because linear factors are not coming.

check and reply.

i will asnswer it .

if f(x) =x^3-x^2-12x+18

3 is a zero

so divide f(x) by x-3 using long division

we get f(x) = (x-3) (x^2+2x-6)

the roots of x^2+2x+6 are imaginary

and they are -1+2.2i and -1 -2.2i

so

x^3-x^2-12x+18 =(x-3)(x-(-1+2.2 i)) (x-(-1-2.2 i))

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