For the polynomial below, 3 is a zero.
f(x)= x^3 - x^2 - 12x + 18
Express f(x) as a product of linear factors.
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x3−x2−12x+18= (x−3) (x2+2x−6)
Equation to solve is:
The solutions are:
x3−x2−12x+18 = (x−3) (x+ 1-√7) (x +1+√7)
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