Find a polynomial f(x) of degree 3 with real coefficients and the following zeros.
Simplify completely with i's.
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f(x) = (x-1)(x - (3+2i))(x-(3-2i))
f(x) = (x-1)(x - 3-2i) (x-3+2i)
f(x) = (x-1)(x - 3)^2-(2i)^2
f(x) = (x-1)(x^2 - 6x +9)+4
f(x) = (x^3-6x^2 +9x -x^2 + 6x -9)+4
f(x) = x^3-7x^2 +15x -5 answer
answer was incorrect
how dear i have solved all the question
what is the answer?
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