Using a given zero to write a polynomial as a product of linear factors

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For the polynomial below, -2 is a zero. 

f(x) = x^3 - 2x^2 - 6x + 4

Express f(x) as a product of linear factors. 

Oct 16th, 2015

Thank you for the opportunity to help you with your question!

f(x)=x^3-2x^2-6x+4

-2 is a zero

f(x)=(x+2)(x^2-4x+2)

f(x)=(x+2)(x-3.41)(x-0.58)

      =(x+2)(x-(341/100)) (x-(29/50))

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 16th, 2015

The answers I am supposed to get for these when they involve big fractions have been using radicals 

Oct 16th, 2015

yes you can also find roots using that method

lets solve for this

x^2-4x+2

here a=1 b=-4 c=2

x=-b+- sqrt(b^2-4ac)/2a

   x1=4+sqrt(16-8)/2

 x1=2 + sqrt(8)/2


and 

x2=2-  sqrt(8)/2

Oct 16th, 2015

did you get it???

Oct 16th, 2015

Im confused on how id write that

Oct 16th, 2015

directly ask me algebra questions i will give explanations to you.

thanks

Oct 16th, 2015

its simple

f(x)  =  (x+2)    (x-(2+√8/2))     (x-(2-√8/2))

Oct 16th, 2015

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