For the polynomial below, -2 is a zero.

f(x) = x^3 - 2x^2 - 6x + 4

Express f(x) as a product of linear factors.

Thank you for the opportunity to help you with your question!

f(x)=x^3-2x^2-6x+4

-2 is a zero

f(x)=(x+2)(x^2-4x+2)

f(x)=(x+2)(x-3.41)(x-0.58)

=(x+2)(x-(341/100)) (x-(29/50))

The answers I am supposed to get for these when they involve big fractions have been using radicals

yes you can also find roots using that method

lets solve for this

x^2-4x+2

here a=1 b=-4 c=2

x=-b+- sqrt(b^2-4ac)/2a

x1=4+sqrt(16-8)/2

x1=2 + sqrt(8)/2

and

x2=2- sqrt(8)/2

did you get it???

Im confused on how id write that

directly ask me algebra questions i will give explanations to you.

thanks

its simple

f(x) = (x+2) (x-(2+√8/2)) (x-(2-√8/2))

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up