go ahead

stats test 4 .The National Institute of Health randomly selected 520individuals who gave blood during the month of May in order todetermine their blood types. The NIH plotted the percentage of theblood types in the pie chart depicted below. What is the number of individuals from this sample who have blood type B? 16 20 28 36 104 5. Regarding the pie chart image presented below (as well as in the question above), what component of a good statistical picture is missing? Title Labeling The Source A Line graph 6 Which of the following might you use to best display categorical data? Histogram Pictogram Line graph Stem plot Scatter plot7. You have collected data on nurses’ annual salaries over a ten-year period (2009 to 2019). Which of the following data organization schemes would best highlight upward and downward changes over time? Pictogram Line graph Bar graph Pie chart Scatterplot 8. Ohio University sorted 150 new students into one of the four residence hall greens as follows: East Green 44, South Green 40, West Green 35, and North Green 31. In a Chi-Square test, what would EXPECTED value (i.e., Expected Frequency) be for the East Green? 37.5 42 44 84 1509. A Chi-square goodness-of-fit test was conducted on voter preferences in a state primary (with candidates A, B, C, and D) that yielded a calculated/obtained statistic of 7.82. If you used a critical value of 6.22 to determine if the voters significantly preferred one candidate over another, what conclusion would you draw? Voters showed no significant preference Voters showed a significant preference Voters showed a significant preference for candidate A over the others Not enough information is given to be able to answer this question Answers B and C are both correct10.Calculate the expected value (i.e., expected frequency) for each cell of the table below, for this Chi-Square Test for Independence. What is the expected value/frequency for the Senior/Yes cell? 22.5 27.5 50 67.5 10011. Ohio University sorted 150 new students into one of the four residence hall greens as follows: East Green 44, South Green 40, West Green 35, and North Green 31. Which is the appropriate test to use to determine whether there was a preference regarding the green to which students were assigned? Goodness of Fit test Test for Independence Parametric test of significance Z-test T-test 12. Which of the following statistical tests would be appropriate to perform on the data in the table depicted here? Goodness of Fit test Test for Independence Parametric test of significance Z-test T-test 13. A potential sponsor would like to know whether local viewers prefer some evening news programs over others. The sponsor conducts a viewer preference survey based on a simple random sample of 260 households. The results are: 54 preferred KTVO, 49 preferred KMDT, 68 preferred KLPF, and 89 preferred KZTV. A goodness-of-fit test performed on these data would yield a calculated/obtained chi-square value of ______: 44.0 / 40.0 2.72 7.90 60.0 / 56.0 14.8014. You flip a coin four times. What is the probability of getting the specific outcome of all heads on each of the four times instead of tails on each of the four times? 0.00 0.50 0.25 1.00 none of the above 15. Event A has a probability of 0.25 and Event B has a probability of 0.00. What is the probability associated with the joint occurrence of these two independent events? 0.00 0.50 0.25 1.00 none of the above 16. Bob has 15 colors of paints. He mixes 2 colors at a time. How many different colors does he get when he mixes all possible pairs of paints? This problem is an example of a _______________: joint probability conditional probability combination permutation "given that" probability17. Let us assume that all 102 students in this course are in one and only one of the following programs: the TAS program, the BA program, or the RN to BSN program. Let us assume further that the number of students in each of these programs is equivalent (in other words, there are 34 students in each program). What is the probability of a student in this course being in either the TAS program or the BA program? 0.1111 0.3333 0.6667 0.9999 cannot be determined 18. A student who is graduating from a large college is randomly selected. Which of the following is the correct wording and interpretation of this probability statement? p(J / N), where J represents the student getting a job, and N represents the student networking with local employers The probability that a randomly selected student gets a job The probability that a randomly selected student gets a job and networks with local employers The probability that a randomly selected student networks with local employers given that the student gets a job The probability that a randomly selected student gets a job given that the student networks with local employers The probability that a randomly selected student gets a job or networks with local employers 19. Ten students from this class are running a race. How many different ways are there for the 10 students to get first, second, and third place? This question is an example of a _____________: joint probability conditional probability combination permutation either/or probability 20. Five students from this class are running a race. How many different ways are there for the 5 students to get first, second, and third place? For this problem, what is N? 3 4 5 6 none of the above21. Five students from this class are running a race. How many different ways are there for the 5 students to get first, second, and third place? For this problem, what is r? 3 4 5 6 none of the above22. Five students from this class are running a race. How many different ways are there for the 5 students to get first, second, and third place? What is the calculated value for this problem? 3 10 15 20 60 23. To drum up business and to get customers to try different varieties of cupcakes, a local bakery is offering one free “luck of the draw” cupcake. That is, a cupcake is randomly selected from what is on hand and given to the customer to try. Currently, the cupcakes available are made of chocolate, vanilla, or strawberry and have one of three toppings: rainbow sprinkles, chocolate chips, or gummy bears. The different configurations of the 100 cupcakes available for the “luck of the draw” promotion are depicted in the table below. What is the probability of receiving a chocolate cupcake with rainbow sprinkles? 0.1395 0.3000 0.0600 0.1000 0.0500 24. To drum up business and to get customers to try different varieties of cupcakes, a local bakery is offering one free “luck of the draw” cupcake. That is, a cupcake is randomly selected from what is on hand and given to the customer to try. Currently, the cupcakes available are made of chocolate, vanilla, or strawberry and have one of three toppings: rainbow sprinkles, chocolate chips, or gummy bears. The different configurations of the 100 cupcakes available for the “luck of the draw” promotion are depicted in the table below.What is the probability that a cupcake is strawberry given that it has rainbow sprinkles? 0.3636 0.3429 0.1200 0.3300 none of the above 25. To drum up business and to get customers to try different varieties of cupcakes, a local bakery is offering one free “luck of the draw” cupcake. That is, a cupcake is randomly selected from what is on hand and given to the customer to try. Currently, the cupcakes available are made of chocolate, vanilla, or strawberry and have one of three toppings: rainbow sprinkles, chocolate chips, or gummy bears. The different configurations of the 100 cupcakes available for the “luck of the draw” promotion are depicted in the table below. What is the probability that a cupcake is vanilla with either rainbow sprinkles or gummy bears? 0.1395 0.2666 0.0880 0.1444 0.130026. (9!) / (5!) = 3,024 5040 43,545,600 604800 In statistics, we cannot divide or multiply factorials27. During which decade was inflation the highest, as measured by the percentage change in the CPI? 1940s 1950s 1960s 1970s 1980s28. What was the rate of inflation during the decade of the 1950s, as measured by percentage change in CPI? 22.82% 31.08% 58.62% 72.14% 112.37% 29. The average price of a new house was $3,395 in 1915, when the CPI was 10.1. How much would the average new house cost in 1995 when adjusted for inflation? (The CPI in 1995 was 152.4.) $34,289.50 $43,580.20 $51,227.52 $73,892.54 $87,652.8930. What was the rate of inflation during the decade of the 1980s, as measured by percentage change in CPI? 22.82% 31.08% 58.62% 72.14% 112.37%31. Using 1989 as a base, the price index for computers is now 185. What does this index number mean? The price of computers has decreased 85% since 1989 The price of computers has increased 85% since 1989 The price of computers has increased 185% since 1989 The price of computers has increased 100% since 1989 The price of computers is now $185 more than in 198932. An economic indicator that is _____________ is one in which the highs, lows, and changes tend to come after or following changes in the economy. leading receding preceding sluggish lagging33. Which one of the following is NOT one of the major uses of the CPI? The CPI is used to evaluate and determine economic policy. The CPI is used to determine economic trends in the rural United States. The CPI is used to compare prices in different years. The CPI is used to determine salary and price adjustments. All of the above answers are major uses of the CPI.34. Much of the rest of the exam is based on the following problem:In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? The appropriate statistical procedure for this problem would be a ___________? t-test z-test Chi-square Goodness of Fit Chi-square Test for Independence Pearson r correlation35. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? What type of test is this? One-tailed Two-tailed Three-tailed Four-tailed Joint conditional probability36. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? The most appropriate alternative hypothesis (in symbols) would be: newmed = 4.75 newmed = 2.60 newmed ≠ 4.75 newmed < 4.75 newmed > 2.60 37. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? The most appropriate null hypothesis (in symbols) would be: newmed = 2.60 newmed = 4.75 newmed > 2.60 newmed > 4.75 newmed < 2.6038. n the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication?For this problem, the correct sign for the critical value should be: + - < > +/-39. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? Which of the following is the critical value associated with an alpha level of .05 that you should use to evaluate the null hypothesis? (Use your tables.) 1.65 1.70 1.96 2.58 2.6040. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? The most appropriate null hypothesis (in words) should be: There is a significant difference in the duration of hospital stay when patients administered the new medication are compared to the general population of patients not receiving this medication. There is no significant difference in the duration of hospital stay when patients administered the new medication are compared to the general population of patients not receiving this medication. Duration of hospital stay is not significantly increased for patients administered the new medication compared to the general population of patients not receiving this medication. Duration of hospital stay is significantly decreased for patients administered the new medication compared to the general population of patients not receiving this medication41. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? The most appropriate alternative hypothesis (in words) would be: There is no significant difference in the duration of hospital stay when patients administered the new medication are compared to the general population of patients not receiving this medication. There is a significant difference in the duration of hospital stay when patients administered the new medication are compared to the general population of patients not receiving this medication. Duration of hospital stay is significantly decreased for patients administered the new medication compared to the general population of patients not receiving this medication. Duration of hospital stay is significantly increased for patients administered the new medication compared to the general population of patients not receiving this medication. 42. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? What is the value of the standard error? 0.36 0.54 1.19 2.10 4.6043. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? Which of the following is the calculated/obtained test statistic for this problem? t = 1.96 z = 1.96 t = 5.91 z = 5.91 z = 2.7144. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? Based on your results, which decision would you make? reject the null hypothesis fail to reject the null hypothesis reject the alternator hypothesis fail to reject the alternator hypothesis retain the alternator hypothesis45. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? The best conclusion for this problem is: There is a significant difference in the duration of hospital stay when patients administered the new medication are compared to the general population of patients not receiving this medication. There is no significant difference in the duration of hospital stay when patients administered the new medication are compared to the general population of patients not receiving this medication. Duration of hospital stay is significantly decreased for patients administered the new medication compared to the general population of patients not receiving this medication. Duration of hospital stay is significantly increased for patients administered the new medication compared to the general population of patients not receiving this medication. 46. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? If you were to calculate the 99% confidence interval, the mean that you would use in this calculation is ____: 4.60 3.20 4.75 2.60 1.8247. Whenever we reject the null hypothesis, as researchers what type of error are we most concerned that we may have made? Standard error Null hypothesis error Alternative hypothesis error Type II statistical error Type I statistical error 48. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? If you were to calculate the 99% confidence interval, what is the critical value that you would use? +/- 1.65 +/- 1.70 +/- 1.96 +/- 2.33 +/- 2.58 49. In the general population, patients who are recovering from bronchial pneumonia normally take a mean (average) of 4.75 days to leave the hospital, with a population standard deviation of 1.82 days. Medical personnel at a hospital are trying a new medication that is designed to ease breathing during recovery. What is not currently known is whether the new medication will impact duration of hospital stay. The first sample of 25 patients (n=25) to whom this medication was administered were released from the hospital in a mean (average) of 2.60 days. Based on this result, should the hospital conclude that there is a significant difference in duration of hospital stay because of the new medication? Calculate the 99% confidence interval. Which 2 values will be required to complete the equation for the confidence interval? 2.1416 < µ < 4.2584 1.7319 < µ < 3.4281 1.6609 < µ < 3.5391 1.8068 < µ < 4.5932 0 < µ < 1.96 50. If α = .05 and β = .25, calculate the following: The statistical decision is to reject the null, and H0 (the null) is really false (i.e., Power) .05 .25 .75 .95 .01 51. If α = .05 and β = .25, calculate the following: The statistical decision is to fail reject the null, and H0 (the null) is really true (i.e., a correct decision) .05 .75 .20 .01 .9552. If α = .05 and β = .25, calculate the following: The statistical decision is to reject the null, and H0 (the null) is really true (i.e., a Type I error) .05 .99 .20 .95 .01 53. If α = .05 and β = .25, calculate the following: The statistical decision is to fail to reject the null, and H0 (the null) is really false (i.e., a Type II error) .05 .25 .75 .95 .01

Find an example of data in the news or on social media and share it in the Discussion Board. If you find your data in an online source, please include the link to the source in your post. Describe the type of data in your example, and what questions you have around the validity of the data. Is there anything misleading or unclear about the way the data is presented?