How many grams were released as water vapor?

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Copper carbonate hydrate produces 1 mole of water (MM = 18.015 g/mol) for every mole of solid product (MM = 79.545 g/mol) produced.  Given that 3.327 g of solid product were produced during the reaction, how many grams of water were released as water vapor?  (number of moles = mass (g)/ molar mass (g/mol)). 

Oct 17th, 2015

Thank you for the opportunity to help you with your question!

3.327 g divided by 79.545 g/mol = 0.0418 moles of solid product.

Therefore, the amount of water released as water vapor is

18.015 g/mol X 0.0418 mol = 0.753 grams of water vapor

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 17th, 2015

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Oct 17th, 2015
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