I have a group of twelve students, 7 male and 5 female.

a. How ways can I pick 4 students from this group?

b. How many ways can I appoint a czar and assistant czar from this group of students?

c. How many ways can pick a committee of 3 students consisting of 1 male and 2 female?

d. How many ways can I choose five students given that at least 3 must be female?

Thank you for the opportunity to help you with your question!

(12*11*10*9) \ 4*3*2 = 495 ways

for a czar is 1 of 12 and for assistant czar is 1 of 12 as well --> the chance

one way

5c3 is 10 ways

5! \ (5-3)!3! = 120\12 = 10 ways

part C does not fully answer the question, it is asking the probability.

is that what you mean

Yes! Thank you

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