Solve sin^2(2x-pi/3)=1/4 for all solutions in the interval [0,2pi)
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sin (2x-pi/3)= 1/2 or sin (2x-pi/3)= -1/2
for sin (2x-pi/3)= 1/2, the solutions satisfies
2x-pi/3 = pi/6, 2x-pi/3 = 5pi/6, 2x-pi/3 = 13/6 pi or 2x-pi/3 = 17/6 pi
the solututions are
x = pi/4, x = 7pi/12, x = 5pi/4, or 19pi/12
for sin (2x-pi/3)= -1/2, the solutions satisfies
2x-pi/3 = 7pi/6, 2x-pi/3 = 11pi/6, 2x-pi/3 = -1/6 pi or 2x-pi/3 = 19pi/6 pi
the solutions are
x = 3/4pi, x = 13/12 pi, x = pi/12, x=7/4pi
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