The length of a rectangle is 3 centimeters more than the width. If both the width and length were doubled, the area would be 112 square centimeters. Find the dimensions of the original rectangle

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let x represent the width of the rectangle

length=x+3

area = 2(x)*2(x+3)=112cm^2

4x^2+12x=112cm^2

x^3+3x=28

x^3+3x-28=0

solving for x = 28

width =28

length=31

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