solving with rational expressions

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Pygevfu

Mathematics

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Solve the equation for x.

x over 3 equals space 1 over 6 plus x over 4


a. 2

b. 6

c. 12

d. 1



Find all solutions for x. 

fraction numerator x squared minus 14 over denominator 2 x end fraction equals space minus fraction numerator 5 over denominator 2 x end fraction


a. 4

b. 3, -3

c. 2

d. 2,-2



Find all solutions for x. 

fraction numerator 1 over denominator x minus 1 end fraction equals fraction numerator 2 over denominator x plus 1 end fraction


a. 3

b. -3

c. 1

d. -1



Solve the equation for x. 

fraction numerator 2 over denominator x squared minus 4 end fraction equals fraction numerator 1 over denominator 2 x minus 4 end fraction


a. 2,  -2

b. 2

c. -2

d. No Solution



Solve the equation for y.

1 space minus space fraction numerator 5 over denominator y plus 7 end fraction equals fraction numerator negative 9 over denominator y plus 7 end fraction


a. 7

b. -7

c. -11

d. No Solution




Solve the equation for x. 

fraction numerator x squared plus 5 over denominator x end fraction minus 1 equals fraction numerator 5 left parenthesis x plus 1 right parenthesis over denominator x end fraction


a. 0,6

b. 6

c. 1, 5

d. 5, 6



Solve the equation below for x.

x space plus space 2 space equals space 8 over x


a. 4, 2

b. -4, -2

c. 4, -2

d. -4, 2



Solve the equation for x.

fraction numerator 1 over denominator x plus 4 end fraction equals fraction numerator 2 over denominator x squared plus 3 x minus 4 end fraction minus space fraction numerator 1 over denominator 1 minus x end fraction


a. minus 1 half

b. -1

c. 6

d. No Solution



Solve the equation for x.

fraction numerator 1 over denominator x minus 2 end fraction equals fraction numerator 2 x plus 1 over denominator x squared plus 2 x minus 8 end fraction plus fraction numerator 2 over denominator x plus 4 end fraction


a. 7 over 3

b. minus 7 over 3

c. 11 over 3

d. minus 11 over 3



Solve the equation for x.

fraction numerator x squared minus 23 over denominator 2 x squared minus 5 x minus 3 end fraction plus fraction numerator 2 over denominator x minus 3 end fraction equals fraction numerator negative 1 over denominator 2 x plus 1 end fraction


a. -8

b. 8, -3

c. -7, 3

d. -8, 3




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