##### Help with statistics homework

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Airline passenger arrive randomly and independently at the passenger-screening facility at a major international airport. The mean arrival rate is 7 passengers per minute.

a) compute the probability of no arrivals in a one minute period (to 6 decimals

b)compute the probability that three or fewer passengers arrive in a one minute period (to 4 decimals

c)compute the probability of no arrivals in a15 second period(to 4 decimals

d)compute the probability of at least one arrival in a 15 second period (4

Oct 20th, 2015

Airline passenger arrive randomly and independently at the passenger-screening facility at a major international airport. The mean arrival rate is 7 passengers per minute.

a) compute the probability of no arrivals in a one minute period (to 6 decimals

0/7= Infinite

b)compute the probability that three or fewer passengers arrive in a one minute period (to 4 decimals

P3 or P2 or P1 =3/7+2/7+1/7 =

c)compute the probability of no arrivals in a15 second period(to 4 decimals

15/60  =0.2500

d)compute the probability of at least one arrival in a 15 second period (4

let probability of atleast one be x, Px =1/7+

Oct 20th, 2015

sorry ,i had a problem with connection, wait for a correct answer.

Oct 20th, 2015

Airline passenger arrive randomly and independently at the passenger-screening facility at a major international airport. The mean arrival rate is 7 passengers per minute.

a) compute the probability of no arrivals in a one minute period (to 6 decimals

0/7= 0.000000

b)compute the probability that three or fewer passengers arrive in a one minute period (to 4 decimals

P3 or P2 or P1 =3/7+2/7+1/7 = 6/7=0.8571

c)compute the probability of no arrivals in a15 second period(to 4 decimals

15/60 =0.2500 i.e not dependent on mean arrival

d)compute the probability of at least one arrival in a 15 second period (4

let probability of atleast one be x, Px =1/7+2/7+3/7+4/7+5/7+6/7+7/7= 28/7=4

in 15 seconds = 1/4*4 =1.0000

Oct 20th, 2015

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Oct 20th, 2015
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Oct 20th, 2015
Sep 21st, 2017
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