The system of equations is : 4x+y-3z=11, 2x-3y+2z=9, x+y+z=-3
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4x+y-3z=11, 2x-3y+2z=9, x+y+z=-3
using eqn 3, make z the subject to get, z=-3-y-x
substituting z into eqns 1 and 2
4x+y-3(-3-y-x)=11 and 2x-3y+2(-3-y-x)=9
simplifying this, 7x+4y=2 and -8y=9
from this, y= -9/8
substituting into 7x+4y=2 we get, 7x+4(-9/8)=2 hence 7x=2+9/2=13/2
hence x= 13/14
to find z= -3+9/8-13/14
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