Solving a system of equations with 3 variables

Algebra
Tutor: None Selected Time limit: 1 Day

The system of equations is : 4x+y-3z=11, 2x-3y+2z=9, x+y+z=-3

Oct 20th, 2015

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4x+y-3z=11, 2x-3y+2z=9, x+y+z=-3

using eqn 3, make z the subject to get, z=-3-y-x

substituting z into eqns 1 and 2

4x+y-3(-3-y-x)=11 and 2x-3y+2(-3-y-x)=9

simplifying this, 7x+4y=2 and -8y=9

from this, y= -9/8

substituting into 7x+4y=2 we get, 7x+4(-9/8)=2 hence 7x=2+9/2=13/2

hence x= 13/14

to find z= -3+9/8-13/14

z=157/56

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 20th, 2015

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