The system of equations is : 4x+y-3z=11, 2x-3y+2z=9, x+y+z=-3

Thank you for the opportunity to help you with your question!

4x+y-3z=11, 2x-3y+2z=9, x+y+z=-3

using eqn 3, make z the subject to get, z=-3-y-x

substituting z into eqns 1 and 2

4x+y-3(-3-y-x)=11 and 2x-3y+2(-3-y-x)=9

simplifying this, 7x+4y=2 and -8y=9

from this, y= -9/8

substituting into 7x+4y=2 we get, 7x+4(-9/8)=2 hence 7x=2+9/2=13/2

hence x= 13/14

to find z= -3+9/8-13/14

z=157/56

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up