Solve the system of linear equations using the Gauss-Jordan elimination method.
7x + 5y = 32
-3x + y = -20
Thank you for the opportunity to help you with your question!
we need to change the equations or put them in gaus-jordan method
7 5 32
-3 1 -20 ...........I can't draw the lines here, but i will try to make everything clear
we need to end with this type of this form
0 1 x
1 0 y
to change 7 to 1, we need to multiply the whole equation by 1/7
we end up with
1 5/7 32/7.........................in the first row
to change -3 to zero, we multiply 3 with 1 (from first row) then add top the second row
..........................more to follow, time ran out dear, but will deliver everything!
the zero on the second row will be obtained after adding 3 to eliminate -3
0 22/7 -44/7
So what is the answer, I am still confused? Here are the multiple choices I was given below:
A. (7, -3)
B. (6, -2)
C. (2, -6)
D. (-6, 2)
E. (-7, -2)
no need to replace the second character in R2 since it's already 1
so we now change the second character on R1 (5) to zero!
-5 x 1 then add to 5 gives us zero
-5 x 32/7= -204/7
The full equation after elimination
1 0 32/7
0 1 -204/7
sorry i did other things...let me answer you asap!
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