How do I solve for a? There are multiple answers.

label Algebra
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5


Oct 20th, 2015

Thank you for the opportunity to help you with your question!

Hello Zoe

to solve:

cross multiply the denominators and the numerators, like this

-4a (a-17)=12 (a-17)

then open the brackets like this:

=    -4a^2 + 68a = 12a-204

then, put like terms together to get

-4a^2 + 68a -12a + 204 = 0

to give you

-4a^2 + 56a + 204 = 0

divide all through by 4 to get:

-a^2 + 14a + 51 = 0

Change the sign on first root to get:

a^2 - 14a - 51 = 0

after this, use the various methods of solving quadratic equations, mainly the formula one.

Hope this did assist. Please let me know if you need any clarification. I'm always happy to answer your questions. I will be pleased if you make me your private tutor. Thank you
Oct 20th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
Oct 20th, 2015
Oct 20th, 2015
Sep 22nd, 2017
Mark as Final Answer
Unmark as Final Answer
Final Answer

Secure Information

Content will be erased after question is completed.

Final Answer