In each of four political races, Democrats are believed to have a 60% chance of winning. If so, what is the probability that Democrats will win (please round four decimal places .XXXX)

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None
of the elections?

Probability
of winning = 0.6

Probability
of Not winning = 0.4

Thus
the probability of not winning any of the elections is:

P(winning
None of the elections) =0.4*0.4*0.4*0.4 = 0.0256

At least one of the elections;

P (winning
at least one election) = (0.6*0.4*0.4*0.4) + (0.6*0.6*.04*0.4) + (0.6*0.6*.0.6*04)
+ (0.6*0.6*.0.6*0.6) = 0.0384 +0.0576+0.0864 +0.1296= 0.312

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