##### story problem algebra question

label Algebra
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A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is 30% salt and Solution B is 55% salt. She wants to obtain

ounces of a mixture that is
salt. How many ounces of each solution should she use?
Oct 22nd, 2015

Solution A =3/10 salt Per ounce

Solution B = 11/20 salt per ounce

Let solution A in mixture be x ounce and solution B be Y ounce.

Then,

3/10 x + 11/20 y = (35*140)/100

X + y = 140

Or

6x +11y=940

X +y = 140

Then

6x+11y =940

6x +6y = 840

Thus

5y = 100 and y = 20

Meaning that

x + 20 =140 thus x = 120

Thus the scientists should use 120 ounces of solution A and 20 ounces of solution B

Oct 22nd, 2015

I have noticed a mistake i made, Kindly use this as the solution to the questions.

Solution A =3/10 salt Per ounce

Solution B = 11/20 salt per ounce

Let solution A in mixture be x ounce and solution B be Y ounce.

Then,

3/10 x + 11/20 y = (35*140)/100

X + y = 140

Or

6x +11y=980

X +y = 140

Then

6x+11y =980

6x +6y = 840

Thus

5y = 140 and y = 28

Meaning that

x + 28 =140 thus x = 112

Thus the scientists should use 112 ounces of solution A and 28 ounces of solution B

Oct 22nd, 2015

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Oct 22nd, 2015
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Oct 22nd, 2015
Sep 23rd, 2017
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