story problem algebra question
Algebra

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A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is 30% salt and Solution B is 55% salt. She wants to obtain
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Solution A =3/10 salt Per ounce
Solution B = 11/20 salt per ounce
Let solution A in mixture be x ounce and solution B be Y ounce.
Then,
3/10 x + 11/20 y = (35*140)/100
X + y = 140
Or
6x +11y=940
X +y = 140
Then
6x+11y =940
6x +6y = 840
Thus
5y = 100 and y = 20
Meaning that
x + 20 =140 thus x = 120
Thus the scientists should use 120 ounces of solution A and 20 ounces of solution B
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I have noticed a mistake i made, Kindly use this as the solution to the questions.
Solution A =3/10 salt Per ounce
Solution B = 11/20 salt per ounce
Let solution A in mixture be x ounce and solution B be Y ounce.
Then,
3/10 x + 11/20 y = (35*140)/100
X + y = 140
Or
6x +11y=980
X +y = 140
Then
6x+11y =980
6x +6y = 840
Thus
5y = 140 and y = 28
Meaning that
x + 28 =140 thus x = 112
Thus the scientists should use 112 ounces of solution A and 28 ounces of solution B
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