A care traveling with a velocity of 20 m/s decelerates uniformly at -5.0 m/s^2 until it comes to rest. what is the total distance the care travels as it decelerates to rest?

Thank you for the opportunity to help you with your question!

You must use the constant acceleration equation 2a(x_final - x_initial)=v_final^2 - v_initial^2 where a is acceleration x is position and v is velocity. Plugging in you get

2(-5)(x_final - 0)=0 - 20^2 (because you start at position 0 and the final velocity is 0 because you come to a stop)

So this simplifies to

-10x_final=-400. Divide both sides by -10.

x_final=40 m

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