I need to know which formula is used and how to show work for it

Physics
Tutor: None Selected Time limit: 1 Day

A care traveling with a velocity of 20 m/s decelerates uniformly at -5.0 m/s^2 until it comes to rest. what is the total distance the care travels as it decelerates to rest? 

Oct 22nd, 2015

Thank you for the opportunity to help you with your question!

You must use the constant acceleration equation 2a(x_final - x_initial)=v_final^2 - v_initial^2 where a is acceleration x is position and v is velocity. Plugging in you get

2(-5)(x_final - 0)=0 - 20^2 (because you start at position 0 and the final velocity is 0 because you come to a stop)

So this simplifies to

-10x_final=-400. Divide both sides by -10.

x_final=40 m

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 22nd, 2015

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