A care traveling with a velocity of 20 m/s decelerates uniformly at -5.0 m/s^2 until it comes to rest. what is the total distance the care travels as it decelerates to rest?
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You must use the constant acceleration equation 2a(x_final - x_initial)=v_final^2 - v_initial^2 where a is acceleration x is position and v is velocity. Plugging in you get
2(-5)(x_final - 0)=0 - 20^2 (because you start at position 0 and the final velocity is 0 because you come to a stop)
So this simplifies to
-10x_final=-400. Divide both sides by -10.
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