What is the maximum mass of S8 that can be produced by combining 93.0 g of each

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Oct 23rd, 2015

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8SO2+16H2S ---> 3S8+16H2O

64*8     16*34         3*8*32     16*18

512        544              768          288

544>512, it needs more H2S than SO2 in the reaction, so the amount of products should be calculated by using H2S

768/544 = x/93

x = 768/544*93 

=131.3 g

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 23rd, 2015

thank you!!! 

Oct 23rd, 2015

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