What is the mass (in grams) of 9.95 × 1024 molecules of methanol (CH3OH)?

Chemistry
Tutor: None Selected Time limit: 1 Day

Oct 23rd, 2015

Thank you for the opportunity to help you with your question!

first we calculate  the mass of 1 mole of CH3OH? 

C = 12 
H3 = 3x1 = 3 
O = 16 
H =1 

Total 32g So we know 6.02x10^23 molecules weigh 32g 

So 1 molecule weighs 32/6.02x10^23 g 
So 9.95x10^24 molecules weighs 9.95x10^24 x (32/6.02x10^23) = 9.95x32x10/6.02=99.5x32/6.02=528.90g

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 23rd, 2015

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