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2NaI(aq) + Cl2(g)===>I2(s) + 2NaCl(aq)
2(150)g NaI + 71gCl2===>254g I2 + 117g NaCl
300g NaI + 71gCl2===>254g I2 + 117g NaCl
254g I2 is produced from=300g NaI
85.6g I2 is produced from=(300/254)*85.6=101.1g
answer is 101.1g
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