how many grams of iodine NaI must be used to produce 85.6g of iodine I2?

Chemistry
Tutor: None Selected Time limit: 1 Day

Oct 23rd, 2015

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2NaI(aq) + Cl2(g)===>I2(s) + 2NaCl(aq)

2(150)g NaI + 71gCl2===>254g I2 + 117g NaCl

300g NaI + 71gCl2===>254g I2 + 117g NaCl

254g I2 is produced from=300g NaI

85.6g I2 is produced from=(300/254)*85.6=101.1g

answer is 101.1g 

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Oct 23rd, 2015

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