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The most important thing to note is,the number of moles before and after dilution will be the same.
volume = 87 ml = 0.087 l
Molarity, M = 0.4M
we know the number of moles is given by;
molarity x volume
assuming the volume added is x liters
volume = (0.087 + x) l
Molarity = 0.1M
number of moles = 0.1 (0.087 + x ) = (0.0087 + 0.1x)moles
0.0348 = 0.0087 + 0.1x
thus; 0.1x = 0.0348 - 0.0087 = 0.0261
dividing both sides of the equation by 0.1;
x = 0.0261/0.1 = 0.261 l =( 0.261 x 1000) ml
The volume of water that is added is; 261 ml
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