Need to find equation for this Math problem
Algebra

Tutor: None Selected  Time limit: 1 Day 
If i gave you 3 random points on a graph and i asked you to develop an exponential equation that would work for those 3 points, could you find its equation? I guarantee NONE of y'all could develop one and as a high school student, i figured out how to find its exponent, multiplier, and constant. I dare you to accept the challenge and prove me wrong ;) Develop en EXPONENTIAL EQUATION FOR THE POINTS: (4,1) (11,11) (13,121) REMEMBER AN EXPONENTIAL EQUATION LOL AND MY IQ IS 178
Thank you for the opportunity to help you with your question!
EQUATION IS((3^n )+ n, 11^(n1)
x coordinate will be given by (3^n )+ n
y coordinate will be given by 11^(n1)
Please let me know if you need any clarification. I'm always happy to answer your questions.hey man thank you for actually taking the time to look at my question. Before you ask me to pay you anything I posted this question to see if any of y'all intellectuals could answer this question successfully. I did not ask you for a relationship in regards of "n". I gave you 3 points and asked you to find its exponential equation, giving me a defined exponent, multiplier, and constant. Since i gave you 3 given points, you can simplify the answers with true numerical answers. If i want to find the intercepts all i do is plug in "0" in the equation to find the y intercept and set the equation = to 0 for the x intercept. I do not need any help as i am here because i am bored out of my brains wanting beef with the smartest instructor on this site who would be more interested than what ends up in his bank account. I have a graphing notebook with me with the answers calculated. This is stuff i made up for my own creativity. This is what they didn't teach you in school even though they SHOULD HAVE. The equation should look something like y= (m(xa)^n)+b I made up the variables but it shouldn't matter because what ISN'T made up is the 3 points i gave you along with their exponential equation.
got you
formulating the three equations
eq 1
1= m(4a) + b
b= 1 4m +ma
eq 2
11= m (11a)^2 + b
eq 3
121 = m(13 a)^3 + b
Always assuming your customers are clueless because you want money... I remain correct, Yet again. You aint gonna prove me wrong bud and I KNOW you wont and thats engraved in stone.
wait sorry i thought you abandoned me lol
no no no no no. no. no. You are misunderstanding the puzzle to a severe degree. There is Only One Equation I want you to give me. There is not 3 equations. There is only One. I gave you 3 Points. I give you 3 Points because it fully constrains all possibilities as i ask you to give me a working exponential equation. When You give me the equation I want you to tell me the exponent, multiplier, and constant along with where the equation translates parallel to the x axis (x  number). Give me true blue numbers. I do not want you to give me m or b or n or any other variable. I promise you that this is out of sheer boredom man I'm not trying to get free answers from anywhere. The equation should look something like y= (multiplier(x number)^exponent)+ constant. Again: Find the exponent, multiplier, constant. No Variables. I want TRUE BLUE NUMBERS LIKE 1,2,3, 4.67, 6,45, ETC. FOR EXAMPLE
Im not lying trust me. Hint: the exponent is between 8 and 14. the multiplier is a very small number. Give the answer to 3 significant figures so i know you got the numbers with accuracy. I did use a graphing calculator for the logBASE function too so you need one too or anything with a log function.
Ill give you the answer after your next response if you dont give me what i want to prove i am legit.
That's it. My patience is gone. Here is the answer: y=(.000000044053(x4)^9.88764)+1 AND THATS ALL YOU NEEDED TO DO :D
Hope you learned something Mr. Tutor!
Thats actually correct. I was still working on it
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