Physics problem to solve

Tutor: None Selected Time limit: 1 Day

A 200 g block is pressed against a spring of force constant 1.40 kN/m until the block compresses the spring 10.0 cm. The spring rests at the bottom of a ramp inclined at 60◦ to the horizontal. Using energy considerations, determine how far up the incline the block moves from its initial position before it stops (a) if the ramp exerts no friction force on the block and (b) if the coefficient of kinetic friction is 0.400.

Oct 24th, 2015

Thank you for the opportunity to help you with your question!

(a)initial potential energy of spring = final gravitational potential energy of block 

The potential energy of a spring is: U = ½kx2

Final gravitational potential energy of the block

Workby gravity = mg(h)

 ½kx2= mgh Thus  since we have the angle  the potential  energy   equlas to  the gravitational energy  on the block

kx^2 / 2 = mgLsinθ 

L = kx^2 / [2mgsinθ] 

L = (1400 N/m)(0.100 m)^2 / [2(0.200 kg)(9.81 m/s^2)(sin60.0°)] 

L = 4.12 m 


Here there  is  an extra  work  done of the friction thus 

initial potential energy of spring = (work of friction) + (final gravitational potential energy of block) 

kx^2 / 2 = μNL + mgh

kx^2 / 2 = μmgLcosθ + mgLsinθ 

L = kx^2 / [2mg(μ*cosθ + sinθ)] 

L = (1400 N/m)(0.100 m)^2 / [2(0.200 kg)(9.81 m/s^2)((0.400)*cos60.0° + sin60.0°)] 

L = 3.35 m

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 24th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
Oct 24th, 2015
Oct 24th, 2015
Mar 24th, 2017
Mark as Final Answer
Unmark as Final Answer
Final Answer

Secure Information

Content will be erased after question is completed.

Final Answer