25.000 mL of H2SO4 was titrated with 0.150 M KOH. The end point was reached when 31.56 mL of KOH was added. Calculate the concentration of the H2SO4.
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We have the reaction as
H2SO4 +2KOH -->K2SO4 +2H2O
Calculating the mole of KOH.
Given molarity =.150M
Volume of KOH required to reach the end point =31.56mL=.03156L
Now the mole is given by=Molarity*volume =.03156.150 =.004734 mole
Now ,from the reaction 2 mole of KOH will react with 1 mole of H2SO4
Therefore .004734 mole will react with .004734/2 mole =.002367 mole.
Now the molarity of H2SO4=mole/vol(liter) =.002367/(.025)=.09468 M(answer)
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