Assigning Oxidation Numbers

Chemistry
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CH(subscript 3)Cl

Oct 25th, 2015

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CH3Cl 

x3*-2=-1

x=5

The oxidation number is 5 since hydrogen is a molecule so it exists in H2 hence 3*2 = 6 and chlorine ion -1 and CH3+ 

is the individual oxidation number of the existing elements in the question
Oct 25th, 2015

i have none thanks for the opportunity

Oct 25th, 2015

C= -2, H =+1, Cl= -1

Oct 25th, 2015

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