f(x) = x^3 - 3x^2 - 9x + 6 x values: -3,-2,-1,0,1,2,3,4
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We have the polynomial function as y=x^3-3x^2-9x+6
To graph the function,we have to find the point of maxima and minima.
Differentiate the function with respect to x and equate it to zero,
Solve for x
x=-1 and x=3
To determine whether maxima or minima occurs differentiate again and substitute the critical value of x
if d^2y/dx^2 >0 then minima occurs
and d^2/dx^2 <0 ,maxima occurs
At x=-1 d^2y/dx^2 <0 therefore maxima occurs and maximum value is f(-1)=11
at x=3 minima ocur as d^2y/dsx^2 >0 ,At x=3 f(3)=-21
Also the y intercept are (0,6)
Using the above information creating a table of values
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