f(x) = -x^3 + 9x + 3 x values: -3,-2,-1,0,1,2,3

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The answer :

we have : f(x) = -x^3 + 9x + 3

so : at the point

x = - 3 ; f(-3) = 3 so (-3,3)

x = - 2 ; f(-2) = -7 so (-2,-7)

x = - 1 ; f(-1) = 13 so (-1,13)

x = 0 ; f(0) = 3 so (0,3)

x = 1 ; f(1) = 11 so (1,11)

x = 2 ; f(2) = 13 so (2,13)

x = 3 ; f(3) = 3 so (3,3)

so we have to put this point on one landmark then draw the line :

graph of a polynom.JPG

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