f(x) = -x^3 + 9x + 3 x values: -3,-2,-1,0,1,2,3
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The answer :
we have : f(x) = -x^3 + 9x + 3
so : at the point
x = - 3 ; f(-3) = 3 so (-3,3)
x = - 2 ; f(-2) = -7 so (-2,-7)
x = - 1 ; f(-1) = 13 so (-1,13)
x = 0 ; f(0) = 3 so (0,3)
x = 1 ; f(1) = 11 so (1,11)
x = 2 ; f(2) = 13 so (2,13)
x = 3 ; f(3) = 3 so (3,3)
so we have to put this point on one landmark then draw the line :
graph of a polynom.JPG
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