A car starts from rest with a constant acceleration of 6m/s^2. How far does it go before reaching a speed of 35 m/s
Thank you for the opportunity to help you with your question!
You want to use this kinematic equation. Also known as a constant acceleration equation.
vf^2=vi^2+2ad where vf is the final velocity, vi is the initial velocity, a is acceleration and d is the distance.
vf=35 because this is the ending speed.
vi=0 because it starts from rest.
a=6 because that was given to you in the problem.
d=distance which will be solved.
1225=12d Now divide both sides by 12.
102.0833333333...=d where d is in meters. The ... just means the 3 repeats forever.
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