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A car starts from rest with a constant acceleration of 6m/s^2. How far does it go before reaching a speed of 35 m/s

Oct 26th, 2015

Thank you for the opportunity to help you with your question!

You want to use this kinematic equation. Also known as a constant acceleration equation.

vf^2=vi^2+2ad where vf is the final velocity, vi is the initial velocity, a is acceleration and d is the distance.

vf=35 because this is the ending speed.

vi=0 because it starts from rest.

a=6 because that was given to you in the problem.

d=distance which will be solved.

35^2=0^2+2(6)d

1225=0+12d

1225=12d Now divide both sides by 12.

102.0833333333...=d where d is in meters. The ... just means the 3 repeats forever.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 26th, 2015

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