how to solve Math problem

Algebra
Tutor: None Selected Time limit: 1 Day

Its (3x4y-2)(5x2y7) 3x to the 4 power times  y to the -2 power times 5x to the 2 power times y to the 7 power?

Oct 27th, 2015

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(3x^4y^-2)(5x^2y^7)

=3*5x^2*x^4*y^-2*y^7

= 15 x^(2+4)y^(-2+7)                      (because a^m*a^n = a^(m+n) )

= 15 x^6 y^5..................................ANSWER


answer is

15 x^6 y^5       ( that is 15 *x power 6*y power 5)


hope you understood..please message if you have any doubts...thank you
Oct 27th, 2015

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