Find dy/dx, and d^2y/dx^2 and evaluate

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Find dy/dx, and d^2y/dx^2 and evaluate the second derivative at the point  x=1 and x=2, Question #1: y=x^5+4x^2+3x

Oct 27th, 2015

Thank you for the opportunity to help you with your question!

dy/dx=5x^4+8x+3

d^2y/dx^2=20x^3+8

The second derivative for x=1 is...

20(1)^3+8=28

The second derivative for x=2 is...

20(2)^3+8=168

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 27th, 2015

thank you so much for helping me. I would like to know why is it 4+8x

Oct 27th, 2015

5x^4  +  8x  +  3?

I spaced it out to show the different terms.

Oct 27th, 2015

The second derivative is

20x^3  +  8

Just to separate the terms for that as well.

Oct 27th, 2015

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