Find dy/dx, and d^2y/dx^2 and evaluate the second derivative at the point x=1 and x=2, Question #1: y=x^5+4x^2+3x

Thank you for the opportunity to help you with your question!

dy/dx=5x^4+8x+3

d^2y/dx^2=20x^3+8

The second derivative for x=1 is...

20(1)^3+8=28

The second derivative for x=2 is...

20(2)^3+8=168

thank you so much for helping me. I would like to know why is it 4+8x

5x^4 + 8x + 3?

I spaced it out to show the different terms.

The second derivative is

20x^3 + 8

Just to separate the terms for that as well.

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up