Thermo Chemistry Determine The Heat Of Dissolution Lab Report

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Question Description

1. In the laboratory a general chemistry student finds that when 2.47 g of CaBr2(s) are dissolved in 110.90 g of water, the temperature of the solution increases from 22.84 to 25.63 °C.

The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.79 J/°C.

Based on the student's observation, calculate the enthalpy of dissolution of CaBr2(s) in kJ/mol.

Assume the specific heat of the solution is equal to the specific heat of water.

ΔHdissolution = kJ/mol


2. In the laboratory a general chemistry student finds that when 1.99 g of CaBr2(s) are dissolved in 105.50 g of water, the temperature of the solution increases from 23.94 to 26.30 °C.

The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.82 J/°C.

Based on the student's observation, calculate the enthalpy of dissolution of CaBr2(s) in kJ/mol.

Assume the specific heat of the solution is equal to the specific heat of water.

ΔHdissolution = kJ/mol

3. Using standard heats of formation, calculate the standard enthalpy change for the following reaction.


CH4(g) + 2O2(g)CO2(g) + 2H2O(g)

ANSWER: kJ


4. Using standard heats of formation, calculate the standard enthalpy change for the following reaction.

NH4NO3(aq)N2O(g) + 2H2O(l)

5. A scientist measures the standard enthalpy change for the following reaction to be 2880.0 kJ :


6CO2(g) + 6 H2O(l)C6H12O6 + 6 O2(g)

Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is kJ/mol.

6. A scientist measures the standard enthalpy change for the following reaction to be -1055.6 kJ :

2H2S(g) + 3 O2(g)2H2O(g) + 2 SO2(g)

Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(g) is kJ/mol.

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Tutor Answer

PDaven
School: UT Austin

Attached.

Outline
Introduction
Body
Conclusion
Reference


Outline
Introduction
Body
Conclusion
Reference


RUNNING HEAD:

Chemistry

Course name:
Student name:
Institution name:

1

RUNNING HEAD: Chemistry

1. The temperature change was observed to be 22.84 to 25.63 °C. which =25.63-22.84=
2.79°C
The heat change Q=-CΔT
Where C= - (mass of the mixture) × (specific heat of the mixture)
2.47 g +110.90 g=113.37g
Q=113.37g×1.79 J/°C×2.79°C=-566.1812J

𝑄

ΔHdissolution = 𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑚𝑜𝑙𝑒𝑠 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑒 =

−566....

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