evaluating a quadratic expression : integers

label Algebra
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5


Oct 28th, 2015

Thank you for the opportunity to help you with your question!

To evaluate a quantratic expression we use the quadratic formula below:

We assume the equation looks like this 

ax2 +bx +c

The value of x is given by:

In our equation  b2 + 6b +9 can alos be written as 

x2 + 6x +9

According to the formula the value of a is 1, the value of b is 6 and the value of c is 9. Please notice that I have replaced b with x to make it easy to understand.

Filling the formula with the values gives

(-6 (+ or -) Square root of ( 62 - 4(1 *9))/2(1)

Solving the square root part

Square root of (36-36) is 0

Solving Further

-6 (+ or -) 0 all of it divided by 2 gives:


The value for b in the expression is -3

Notice how easy it was because the square root part gave us a zero.

if you want to know how the quadratic formula is arrived at, please look at the following tutorial:


Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 28th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
Oct 28th, 2015
Oct 28th, 2015
Jun 29th, 2017
Mark as Final Answer
Unmark as Final Answer
Final Answer

Secure Information

Content will be erased after question is completed.

Final Answer