Description
Degree 4; zeros: 4-3i; -5 multiplicity 2
Explanation & Answer
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(x-(-5))^2(x-(4-3i))(x-(4+3i))=0 is the answer.
The multiplicity of two means that the root is raised to the 2nd power. For complex numbers that are zeros the conjugate of the number is always a zero as well. To get the conjugate of a complex number like 4-3i you just change the sign in front of the term with the i in it. So the conjugate is 4+3i. Then to write the function you just subtract the zeros from x in parantheses for each zero and multiply them all together and set equal to 0.
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