Half-life word problems.

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Carbon-14 is a radioactive compound that occurs naturally in all living organisms, with the amount in the organism constantly renewed. After death, no new carbon-14 is acquired and the amount in the organism begins to decay exponentially. If the half-life of carbon-14 is 5730 yr, how old is a mummy having only 45 % of the normal amount of carbon-14?

I know this is A=AoPe^(rt) but I cant quite get it, I know the answer is 6600 years but not the method. Half life goes up as percentage goes down?

Oct 29th, 2015

Thank you for the opportunity to help you with your question!

We  have the formula as

N=Amount after n half life

N0=Initial amount

n= number of half life

The time taken=half life the element*n

Given

Substitute in the above formula to find n

So we have the value of n=1.15209

The time taken=n*half life=1.15209*5730 yr=6600 yr.

--ANSWER------

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 29th, 2015

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Oct 29th, 2015
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Oct 29th, 2015
Jun 23rd, 2017
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