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BCN4431 FIU Concrete Design Homework Questions Help

BCN4431

Florida International University

Question Description

Attached is the assignment questions, make sure to use correct number the PID to use is 6086509.

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BCN 4431 Spring 2019 Due: April 19, 2019 at 5:00 PM Homework 3 INSTRUCTIONS: All the steps must be clearly shown. Whenever a value or any other information comes from book or code, table number and/or page number should be clearly mentioned. If any value that you need for calculations is not given, assume and state the basis of your assumption (based on book, reasoning etc.). (If your PID is “5684659”, then A = 5, B = 6, C = 8, D = 4, E = 6, F = 5 and G = 9. Interpret 4.G as 4.9 in this example) 1. (5 points) Determine Mn for a beam of cross section shown in figure 1, where f’c = 4 ksi. Assume fy = 60 ksi. Calculate the strain on steel when the concrete strain is 0.003 and compare it with yield strain of steel. Es = 29x103 ksi Figure 1 1 2. (5 points) Determine if the beam shown in the figure is adequate as governed by the ACI Code (318-11). The loads shown are service loads. The uniformly distributed load is DL = 0.65 + 0.F = _________ kip/ft, LL = 0.55 + 0.E = ________ kip/ft. The dead load excludes the beam weight. The point load is a live load. f’c = 3,000 psi, fy = 40,000 psi. In case you find that the section is not tension-controlled, use the closest value of ݇. ONLY FOR THE SAKE OF SIMPLIFYING THIS PROBLEM, SHOULD NOT BE FOLLOWED ELSEWHERE. 2 ...
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Final Answer

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Running head: Concrete design homework

Concrete design homework
Name of student
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1

Concrete design homework
2
Question one
Given that;
PID it is 6086509 where A=6, B=O, C=8, D=6, E=5, F=0, G=9, f’c= 40 ksi, fy = 60 ksi, concrete
strain is 0.003 and yield strain of steel Es= 29x10^3ksi.
Nominal moment capacity Mn= p*bd^2*fy (1-0.59 p* fy/ f’c)
Mn= p*bd^2*fy (1-0.59 p* fy/f’c)
Where p= As/b*d
As*fy = 0.85f’c ab
a=ẞ*c
c=ϵu/ (ϵu+fy) *d where ϵu= concrete strain
ϵu= 0.003, fy=60 ksi and d =20.A’’ where A= 6 hence d= 20.6=20.6’’
c=ϵu/ (ϵu+fy) *d = 0.003/ (0.003+4...

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