How do I calculate the moles and mass of the positive ions in 4.39 g of ammonium iodide, NH4I; 6.48 mol of ammonium sulfide, (NH4)2S;
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We have the formula for the calculation of mole=weight/molecular weight
Wight =4.39 g
Mole=weight/Molecular weight =4.39/145 =.03 mole
Here the positive ion is NH4+,so its molecular mass =18
So the mass of positive ion NH4+ =18*.03 g=.545 g(answer)
b)6.48 mole of ammonium sulfide, (NH4)2S
Here the positive ion is 2NH4+ ,From the compound 1 mole of (NH4)2S contain 2 mole of NH4+
Therefore the mole of NH4+=2*6.48=12.96 mole
Mass of positive ion it contain=Molecular weight of NH4+*mole =12.96*18=233.28 gram(answer)
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