How do I calculate the moles and mass of the positive ions in 4.39 g of ammonium?

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How do I calculate the moles and mass of the positive ions in 4.39 g of ammonium iodide, NH4I; 6.48 mol of ammonium sulfide, (NH4)2S;

Oct 30th, 2015

Thank you for the opportunity to help you with your question!

We have the formula for the calculation of mole=weight/molecular weight

For NH4I

Wight =4.39 g

Mole=weight/Molecular weight =4.39/145 =.03 mole

Here the positive ion is NH4+,so its molecular mass =18

So the mass of positive ion NH4+ =18*.03 g=.545 g(answer)

b)6.48 mole of ammonium sulfide, (NH4)2S

Here the positive ion is 2NH4+ ,From the compound 1 mole of (NH4)2S contain 2 mole of NH4+

Therefore the mole of NH4+=2*6.48=12.96 mole

Mass of positive ion it contain=Molecular weight of NH4+*mole =12.96*18=233.28 gram(answer)

---Thanks----------


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Oct 30th, 2015

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