What is the energy of a photon with a frequency of 3.2x10^-2Hz?

Chemistry
Tutor: None Selected Time limit: 1 Day

Hi, I was just wondering how I would attempt to solve the question of how to find the energy of a photon with a frequency of 3.2x10^-2 Hz?

Oct 30th, 2015

Thank you for the opportunity to help you with your question!

E=hf where E is the energy of the photon, h is planck's constant, and f is the frequency.

E=(6.626*10^-34)(3.2x10^-2)=2.12*10^-35 Joules which is the answer.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Oct 30th, 2015

Hi again,

Thank you so much for all of your help in explaining this. I really appreciate it. It really helped. However, I was just wondering how you got 2.12*10^-35 on your calculator, paper, etc. because when I plugged in 6.626*10^-34, I just got 6.626*10^-34, and not an actual answer. Thanks

Oct 30th, 2015

You have to multiply by the frequency (3.2x10^-2). When there is no sign between any terms in an equation it is implied that one should multiply.

Oct 30th, 2015

E=(6.626*10^-34)(3.2x10^-2)=2.12*10^-35 Joules which is the answer.

That is the part you want to look at in my answer.

Oct 30th, 2015

Okay thank you, I figured out what I was doing wrong (however, it wasn't what you were explaining because I already knew that). I just had to clear/reset my calculator settings. Thanks though for helping me and explaining and everything.

Oct 30th, 2015

No problem. Glad you figured it out.

Oct 30th, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Oct 30th, 2015
...
Oct 30th, 2015
Dec 10th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer