##### What is the energy of a photon with a frequency of 3.2x10^-2Hz?

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Hi, I was just wondering how I would attempt to solve the question of how to find the energy of a photon with a frequency of 3.2x10^-2 Hz?

Oct 30th, 2015

E=hf where E is the energy of the photon, h is planck's constant, and f is the frequency.

E=(6.626*10^-34)(3.2x10^-2)=2.12*10^-35 Joules which is the answer.

Oct 30th, 2015

Hi again,

Thank you so much for all of your help in explaining this. I really appreciate it. It really helped. However, I was just wondering how you got 2.12*10^-35 on your calculator, paper, etc. because when I plugged in 6.626*10^-34, I just got 6.626*10^-34, and not an actual answer. Thanks

Oct 30th, 2015

You have to multiply by the frequency (3.2x10^-2). When there is no sign between any terms in an equation it is implied that one should multiply.

Oct 30th, 2015

E=(6.626*10^-34)(3.2x10^-2)=2.12*10^-35 Joules which is the answer.

That is the part you want to look at in my answer.

Oct 30th, 2015

Okay thank you, I figured out what I was doing wrong (however, it wasn't what you were explaining because I already knew that). I just had to clear/reset my calculator settings. Thanks though for helping me and explaining and everything.

Oct 30th, 2015

No problem. Glad you figured it out.

Oct 30th, 2015

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Oct 30th, 2015
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Oct 30th, 2015
Oct 18th, 2017
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