The one-to-one function f is defined here: f(x)=√2x-2

Find f⁻¹, the inverse of f.

Then give the domain of f⁻¹ using interval notation

Thank you for the opportunity to help you with your question!

The answer :

we have : f(x) = sqrt(2x - 2)

so to find the inverse of the function should put : y = sqrt(2x - 2)

so : y² = 2x - 2

so : y² + 2 = 2x

so : x = y²/2 + 1

so : f^-1(x) = (1/2)y² + 1

the domain is : IR

interval natation is : Df^-1 = ]-infinity , 0] U [0 , +infinity[

Please if you don't understand something just ask i will answer youI am glad to work with you just invite me each time you have any others question i will give you the best answersGOod Luck

so I would write it like this: f⁻¹(x)=1/2 and then the domain of f⁻¹=(⁻∞,0)(0,⁺∞)

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