Thank you for the opportunity to help you with your question!
The equation is HCO3
(aq) + H^+ (aq) → H2O (l) + CO2 (g)
Since the gas product (CO2) is released into the atmosphere, the weight loss of the reaction mixture after
the reaction is the amount of CO2 generated in the reaction. So the mass of CO2 is : initial mass-final mass=118.00g-117.318g= 0.682g
According to the balanced chemical equation, it takes one mole of NaHCO3 to produce one mole of CO2.
As a result,
mass of NaHCO3 reacted =
(mass of CO2 generated / M.W. of CO2) × M.W. of NaHCO3
mass of NaHCO3 reacted =(0.682g/44)x84=1.302g
4. The number of moles of NaHCO3 that reacted= mass of NaHCO3 reacted /M.W.
number of moles of NaHCO3 that reacted=1.302g/84=0.0155 moles
Please let me know if you need any clarification. I'm always happy to answer your questions.
Nov 1st, 2015
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