Chemistry help needed to Calculate the number of moles of Alka Seltzer that reacted

Chemistry
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Column 6: Calculate the number of moles of NaHCO3 that reacted in each beaker. (The molar ratio between evolved CO2 and the bicarbonate, HCO3-, is 1:1) 

Note: I used 3g of Alka Seltzer, Initial Mass was(Vinegar+water+alka selt) 118.00g, Final Mass is 117.318g, Mass of Co2 evolved was 0.682g, moles of CO2 evolved was 0.0155g/moles

Nov 1st, 2015

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  1. The equation is HCO3 – (aq) + H^+ (aq) → H2O (l) + CO2 (g) 
  2.  Since the gas product (CO2) is released into the atmosphere, the weight loss of the reaction mixture after the reaction is the amount of CO2 generated in the reaction. So the mass of CO2 is : initial mass-final mass=118.00g-117.318g= 0.682g
  3. According to the balanced chemical equation, it takes one mole of NaHCO3 to produce one mole of CO2. As a result, mass of NaHCO3 reacted = (mass of CO2 generated / M.W. of CO2) × M.W. of NaHCO3
mass of NaHCO3 reacted =(0.682g/44)x84=1.302g
4. The number of moles of NaHCO3 that reacted= mass of NaHCO3 reacted /M.W.
number of moles of NaHCO3 that reacted=1.302g/84=0.0155 moles

Please let me know if you need any clarification. I'm always happy to answer your questions.
Nov 1st, 2015

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