Need help on a Calculus homework question about electrical current

Anonymous
timer Asked: Nov 2nd, 2015
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Question Description

A capacitor has 100V of charge on it.  An electrical current is supplied to it, with .  After .25 seconds, the capacitor has charged to 220 V. What is its capacitance?

Tutor Answer

ipesuni
School: New York University

Thank you for the opportunity to help you with your question!

We have the equation as

i=C*(dV/dt)

i=current,Missing in the question,from different sources I have found the i should be given as i=.25t^2

dV=change in voltage

C=capacitance

It can be written as

idt=CdV

i (dt)=C int(dV)

Integrating both side

int.25t^2**dt=C*(V2-V1)

(.25*t^3)/3=120C*(V2-V1)

Solve

C=.25^4/3*120 farad=1.08*10^-5 F =10.85micro Farad.(answer)



Please let me know if you need any clarification. I'm always happy to answer your questions.

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Review

Anonymous
awesome work thanks

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