Need help on a Calculus homework question about electrical current

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A capacitor has 100V of charge on it.  An electrical current is supplied to it, with .  After .25 seconds, the capacitor has charged to 220 V. What is its capacitance?

Nov 2nd, 2015

Thank you for the opportunity to help you with your question!

We have the equation as

i=C*(dV/dt)

i=current,Missing in the question,from different sources I have found the i should be given as i=.25t^2

dV=change in voltage

C=capacitance

It can be written as

idt=CdV

i (dt)=C int(dV)

Integrating both side

int.25t^2**dt=C*(V2-V1)

(.25*t^3)/3=120C*(V2-V1)

Solve

C=.25^4/3*120 farad=1.08*10^-5 F =10.85micro Farad.(answer)



Please let me know if you need any clarification. I'm always happy to answer your questions.
Nov 2nd, 2015

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