A capacitor has 100V of charge on it. An electrical current is supplied to it, with . After .25 seconds, the capacitor has charged to 220 V. What is its capacitance?
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We have the equation as
i=current,Missing in the question,from different sources I have found the i should be given as i=.25t^2
dV=change in voltage
It can be written as
i (dt)=C int(dV)
Integrating both side
C=.25^4/3*120 farad=1.08*10^-5 F =10.85micro Farad.(answer)
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