Need help with a probability and statistics survey

Statistics
Tutor: None Selected Time limit: 1 Day

A survey of the mean number of cents off that coupons give was conducted by randomly surveying one coupon per page from the coupon sections of a recent San Jose Mercury News. The following data were collected: 20; 80; 55; 65; 30; 55; 40; 40; 30; 55; $1.50; 40; 65; 40. Assume the underlying distribution is approximately normal

x =

sx =

n =

n − 1 =

Which distribution should you use for this problem? (Enter your answer in the form z or tdf where df is the degrees of freedom.)

Nov 3rd, 2015

Thank you for the opportunity to help you with your question!

We have the sample as {20,80,55,65,30,55,40,40,30,55,150,40,65,40}

Here the n=total number of sample =14

n-1=>14-1=13

Mean of the sample =Sum of all observation/total observation =(20+80+55+65+30+55+40+40+30+55+150+40+65+40)/14=54.64

Standard deviation=31.89

We will use the normal distribution ,N(54.64,31.89).

Please let me know if you need any clarification. I'm always happy to answer your questions.
Nov 3rd, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Nov 3rd, 2015
...
Nov 3rd, 2015
Dec 4th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer