##### Need help with a probability and statistics survey

label Statistics
account_circle Unassigned
schedule 1 Day
account_balance_wallet \$5

A survey of the mean number of cents off that coupons give was conducted by randomly surveying one coupon per page from the coupon sections of a recent San Jose Mercury News. The following data were collected: 20; 80; 55; 65; 30; 55; 40; 40; 30; 55; \$1.50; 40; 65; 40. Assume the underlying distribution is approximately normal

x =

sx =

n =

n − 1 =

Which distribution should you use for this problem? (Enter your answer in the form z or tdf where df is the degrees of freedom.)

Nov 3rd, 2015

We have the sample as {20,80,55,65,30,55,40,40,30,55,150,40,65,40}

Here the n=total number of sample =14

n-1=>14-1=13

Mean of the sample =Sum of all observation/total observation =(20+80+55+65+30+55+40+40+30+55+150+40+65+40)/14=54.64

Standard deviation=31.89

We will use the normal distribution ,N(54.64,31.89).

Nov 3rd, 2015

...
Nov 3rd, 2015
...
Nov 3rd, 2015
Oct 20th, 2017
check_circle