Help with math problem

Mathematics
Tutor: None Selected Time limit: 1 Day

Nov 3rd, 2015

Thank you for the opportunity to help you with your question!

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x + 3y = 9 ---(1)

3x - y = 7 ---(2)


Multiply equation (1) by 3

3x + 9y = 27 ---(3)


Subtract equation (2) from equation (3)

3x + 9y - (3x - y) = 27 - 7

3x + 9y -3x + y = 20

10y = 20

y = 20/10

y = 2


Substitute value of y in equation (1)

x + 3(2) = 9

x + 6 = 9

x = 9 - 6

x = 3


So the system of equations has one and only one solution and

the solution is (3, 2).

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Please let me know if you need any clarification. I'm always happy to answer your questions.
Nov 3rd, 2015

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