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7x + 5y = 32
- 3x + y = - 20
from the system of equations above, we can eliminate y by multiplying the first equation by 1 and the second equation by 5 and then we subtract the 2 equations.
1(7x + 5y = 32) = 7x + 5y = 32
(7x + 5y = 32) - (-15x + 5y = - 100) = 22x + 0y = 132
therefore to find x;
22x/22 = 132/22
thus x = 6
to find the value of y, we eliminate x form the equation. this is by multiplying the first equation by 3 and the second equation by 7 and then adding the 2 equations.
3(7x + 5y = 32) = 21x + 15y = 967(- 3x + y = - 20) = - 21x + 7y = - 140
3(7x + 5y = 32) = 21x + 15y = 96
(21x + 15y = 96) + (- 21x + 7y = -140) = 0x + 22y = -44
therefore to find y;
22y/22 = -44/22
y = - 2
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