Find the constants m and b in the linear function f(x) = mx + b so that f(1) = 2 and the straight line represented by f has slope - 1

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f(x)=mx+b

the straight line f(x) has slope m, which is given -1; thus

m=-1 ...(1)

f(x) at x=1

f(1)=2=m+b .....(2)

From equation (1) and equation(2), we have

2=-1+b; b=3

Thus

f(x)= -x+3

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