After one half-life, 50 percent of the parent isotope will have decayed. After the second half-life ______ percent of the original amount will remain.

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Let the total amount of parent isotope be 'X'.

After one half-life,50% of X will have decayed.

So,the remaining amount is (X/2).

After second half-life,50% of (X/2) will have decayed.

So,the remaining amount is half of (X/2).

Remaining amount = X/4.

Percentage of original amount remaining =[(X/4)/X]*100 = 25%

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