After one half-life, 50 percent of the parent isotope will have decayed. After the second half-life ______ percent of the original amount will remain.
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Let the total amount of parent isotope be 'X'.
After one half-life,50% of X will have decayed.
So,the remaining amount is (X/2).
After second half-life,50% of (X/2) will have decayed.
So,the remaining amount is half of (X/2).
Remaining amount = X/4.
Percentage of original amount remaining =[(X/4)/X]*100 = 25%
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